文科数学答案解析.pdf

1、 1 8 2023 2023.03 1 2 3 4 5 6 7 8 9 10 11 12 A C B D D D A C A A C C 13.2 3 ;14.8+4 ;155960 ;16 120cm.17naa3a8=4a2 na cn=nT cn n na1a,2 8 naan=cn=()13122143223nn .1812 2022.ABAB10060106010)1020)2030)3040)4050)5060AB 3 8 A 100A30 B020)221010)AB AAABmnBabcmnmambmcnanbncabacbcmambmcnanbncPAAB 010)2 102

2、0)3 2030)5 3040)15 4050)40 506035 4 8 BBB19 PABMNPNM2ANNPANBM3ANBM=1CDABNP CDPBM PABMN MNQCQDQ DQ DQMP DQBMPMPBMP DQBMPABMNCQMB CQBMPMBBMP CQBMP DQCDQCQCDQDQCQQ CDQBMP 5 8 CDCDQ CDBMP ABMNBBEMNANE AEB2AE2BE AB2=AE2+BE2AEBE BEMN ANNM ANNPNMNPN,NM NPNMP ANNMP ANANMB ANMBNMP PNM2 PNM PABMN 6 8 2012 19.

3、OCF(,0)F3.ACxB,DCBDx CPP1l2l1l2lC1l2l?.7 8 1b C 224xy.,B m n,D mn33m A2 0,2,ABmn2,ADmn 2222224432441433332mAB ADmnmmmmm AB AD0,74 3.(,)P s t224st.1t 12,l l012ll.(,)P s tlk l()ytk xs Cx2+3kx+(t ks)2=3 222(31)6()3()30kxk tks xtks 8 8 222236()4(31)3()30k tksktks 222(3)210s kstkt230s 12,l l12,k k12,k k

4、12ll.CP12ll.21f(x)=ln x+2x+()()f x ()2()()3g xxf xxmn1,g(m)+g(n)0()x0 x f(x)0 0 x ,f(x)0 g(x)=lnx+2x1,g(x)=,x g(x)0 9 8 0 x ,g(x)0 ()g x0,.nm 1nm0n1m 1n g(n)g(1)=0 g(m)+g(n)0 0n11n ,g(n)g(),g(m)+g(n)g()+g(m)=(m+)(mm+)0n1mm+g()+g(m)=(m+)(mm+)0 g(m)+g(n)0,mn1g(m)+g(n)0.10 8 22.4-4 xOyCl x+yxCl ClABABO 1 cossinxy22cos1sincossin1xy C2211xy cos,sinxy l1sin42 C2cos l 11 8 00,4OA OB 23.4-5 f xxx m ,(mR)1m()2f x xf xx 3m 1mf xxx 2112f xxxx 2fx4x4x 2113f xxxx 2fx23x 1x2112f xxxx 2fx0 x1x 2fx 3,4 3,4x 12 8 44xxmx 424mx3,4x 3x24x m4,10